Optimal. Leaf size=114 \[ -\frac{b \text{PolyLog}\left (2,1-\frac{2 c (d+e x)}{(c x+1) (c d+e)}\right )}{2 e}+\frac{b \text{PolyLog}\left (2,1-\frac{2}{c x+1}\right )}{2 e}+\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(c x+1) (c d+e)}\right )}{e}-\frac{\log \left (\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{e} \]
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Rubi [A] time = 0.0807015, antiderivative size = 114, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {5920, 2402, 2315, 2447} \[ -\frac{b \text{PolyLog}\left (2,1-\frac{2 c (d+e x)}{(c x+1) (c d+e)}\right )}{2 e}+\frac{b \text{PolyLog}\left (2,1-\frac{2}{c x+1}\right )}{2 e}+\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(c x+1) (c d+e)}\right )}{e}-\frac{\log \left (\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{e} \]
Antiderivative was successfully verified.
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Rule 5920
Rule 2402
Rule 2315
Rule 2447
Rubi steps
\begin{align*} \int \frac{a+b \tanh ^{-1}(c x)}{d+e x} \, dx &=-\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{e}+\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(c d+e) (1+c x)}\right )}{e}+\frac{(b c) \int \frac{\log \left (\frac{2}{1+c x}\right )}{1-c^2 x^2} \, dx}{e}-\frac{(b c) \int \frac{\log \left (\frac{2 c (d+e x)}{(c d+e) (1+c x)}\right )}{1-c^2 x^2} \, dx}{e}\\ &=-\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{e}+\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(c d+e) (1+c x)}\right )}{e}-\frac{b \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+e) (1+c x)}\right )}{2 e}+\frac{b \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+c x}\right )}{e}\\ &=-\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{e}+\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2 c (d+e x)}{(c d+e) (1+c x)}\right )}{e}+\frac{b \text{Li}_2\left (1-\frac{2}{1+c x}\right )}{2 e}-\frac{b \text{Li}_2\left (1-\frac{2 c (d+e x)}{(c d+e) (1+c x)}\right )}{2 e}\\ \end{align*}
Mathematica [C] time = 0.245294, size = 257, normalized size = 2.25 \[ \frac{-\frac{1}{2} i b \left (-i \text{PolyLog}\left (2,e^{-2 \left (\tanh ^{-1}\left (\frac{c d}{e}\right )+\tanh ^{-1}(c x)\right )}\right )-i \text{PolyLog}\left (2,-e^{2 \tanh ^{-1}(c x)}\right )-\log \left (\frac{2}{\sqrt{1-c^2 x^2}}\right ) \left (\pi -2 i \tanh ^{-1}(c x)\right )+i \left (\tanh ^{-1}\left (\frac{c d}{e}\right )+\tanh ^{-1}(c x)\right )^2+2 i \left (\tanh ^{-1}\left (\frac{c d}{e}\right )+\tanh ^{-1}(c x)\right ) \log \left (1-e^{-2 \left (\tanh ^{-1}\left (\frac{c d}{e}\right )+\tanh ^{-1}(c x)\right )}\right )-2 i \left (\tanh ^{-1}\left (\frac{c d}{e}\right )+\tanh ^{-1}(c x)\right ) \log \left (2 i \sinh \left (\tanh ^{-1}\left (\frac{c d}{e}\right )+\tanh ^{-1}(c x)\right )\right )-\frac{1}{4} i \left (\pi -2 i \tanh ^{-1}(c x)\right )^2+\left (\pi -2 i \tanh ^{-1}(c x)\right ) \log \left (e^{2 \tanh ^{-1}(c x)}+1\right )\right )+a \log (d+e x)+b \tanh ^{-1}(c x) \left (\frac{1}{2} \log \left (1-c^2 x^2\right )+\log \left (i \sinh \left (\tanh ^{-1}\left (\frac{c d}{e}\right )+\tanh ^{-1}(c x)\right )\right )\right )}{e} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.132, size = 148, normalized size = 1.3 \begin{align*}{\frac{a\ln \left ( cxe+cd \right ) }{e}}+{\frac{b\ln \left ( cxe+cd \right ){\it Artanh} \left ( cx \right ) }{e}}-{\frac{b\ln \left ( cxe+cd \right ) }{2\,e}\ln \left ({\frac{cxe+e}{-cd+e}} \right ) }-{\frac{b}{2\,e}{\it dilog} \left ({\frac{cxe+e}{-cd+e}} \right ) }+{\frac{b\ln \left ( cxe+cd \right ) }{2\,e}\ln \left ({\frac{cxe-e}{-cd-e}} \right ) }+{\frac{b}{2\,e}{\it dilog} \left ({\frac{cxe-e}{-cd-e}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{2} \, b \int \frac{\log \left (c x + 1\right ) - \log \left (-c x + 1\right )}{e x + d}\,{d x} + \frac{a \log \left (e x + d\right )}{e} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b \operatorname{artanh}\left (c x\right ) + a}{e x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{a + b \operatorname{atanh}{\left (c x \right )}}{d + e x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{b \operatorname{artanh}\left (c x\right ) + a}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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